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Circular and Satellite Motion 6: Orbital Math

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Assignment Overview

Use circular and orbital motion equations and an understanding of a satellite as a free-falling object to solve the following problems.

 1. CG13Q6
Points: 0/1

Determine the orbital speed (in mi/hr) of a 460-kg satellite that orbits Earth at location that is 1230 miles above Earth's surface. Use the Table of Planetary Data and the fact that 1.0 mile = 1609 m and 1.0 m/s = 2.24 mi/hr.

  1. Orbital Speed

    x10^

    mi/hr

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 2. CG14Q5
Points: 0/2

Consider an orbital location 2400 miles above the Moon's surface. Given that 1 mile = 1609 m, use the Table of Planetary Data to calculate …

  1. … the distance of this location from the center of the Moon.

    Moon-Satellite Distance

    x10^

    m

  2. … the acceleration of gravity at this location.

    Acceleration of Gravity

    m/s/s

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 3. CG14Q6
Points: 0/1

The acceleration of gravity on Earth's surface is 9.8 m/s/s but the value decreases with increasing distance from Earth's center. Determine the altitude above the Earth's surface that you must be located to experience an acceleration of gravity of 1.72 m/s/s. Express your answer in terms of Earth-radii; that is, express the answer as the number of times greater than 6.38x106 m.

  1. Distance from Surface

    * Earth-radii

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 4. CG15Q1
Points: 0/4

A satellite orbits Earth at a location of 296 km above its surface. Use orbital equations to determine the … 

(Given: G = 6.674x10-11 N·m2/kg2; MEarth = 5.974x1024 kg; REarth = 6.378x106 m )

  1. … the orbital radius of the satellite. (Consider using the scientific notation entry field to express your answer.)

    Orbital Radius

    x10^

    m

  2. … the orbital speed of the satellite.

    Orbital Speed

    m/s

  3. … the orbital period of the satellite (in seconds).

    Orbital Period

    s

  4. … the orbital period of the satellite (in hours).

    Orbital Period

    hrs

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 5. CG15Q2
Points: 0/3

Geostationary satellites are satellites which are orbiting the Earth above the equator and make one complete orbit every 24 hours. Because their orbital period is synchronized with the Earth's rotational period, a geostationary satellite can always be found in the same position in the sky relative to an observer on Earth. (GIVEN: MEarth = 5.98 x 1024 kg)

  1. Determine the orbital radius of a geostationary satellite.

    Orbital Radius

    x10^

    m

  2. Determine the orbital speed of a geostationary satellite.

    Orbital Speed

    m/s

  3. Determine the acceleration of a geostationary satellite.

    Orbital Acceleration

    m/s/s

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 6. CG15Q3
Points: 0/4

A satellite with a mass of 535 kg is in circular orbit about the Earth at a height above the Earth equal to 1.30 times the mean radius of the earth. (Rearth = 6.38x106 m and MEarth = 5.98x1024 kg). Determine the … 

  1. … distance of the satellite from Earth's center (in m). Consider using the scientific notation entry field to express your answer.

    Earth-Satellite Distance

    x10^

    m

  2. … the satellite's orbital speed.

    Orbital Speed

    m/s

  3. … the satellite's orbital period (in minutes).

    Orbital Period

    m

  4. … the gravitational force (in Newtons) acting upon the satellite. 

    Force of Gravity

    N

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